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MP_
n00b
Joined: 10 Nov 2003
Posts: 57
Location: Budapest, Hungary
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 Posted: Tue Jun 22, 2004 8:22 pm Post subject: PHP: create object of type by a string |
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OK, so here's my problem:
I have several classes, and I want my script to create objects based on their name.
For example:
| Code: |
class Example { ... }
[...]
$type = 'Example';
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Now I want to know if there is a way to refer to the Example class directly from the string, like I can refer to a certain function or variable, whose name is stored in a string (create an object of type $type automatically).
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Teetante
Guru
Joined: 02 Mar 2004
Posts: 515
Location: Oldenburg/Germany
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| Posted: Tue Jun 22, 2004 11:50 pm Post subject: |
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Thats no problem.
| Code: |
$type = "Foo";
$ref = new $type;
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This should work if the class $type has been declared before.
You could check that:
| Code: |
$type = "Foo";
if(class_exists($type)
{
$ref = new $type;
}
else
{
$ref = NULL;
}
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Semantically identical and shorter would be
| Code: |
$type = "Foo";
$ref = (class_exists($type))?new $type:NULL;
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ICQ #81510866 - http://the-gay-bar.com - MSN tante@emptiness.de
Occam's Razor:
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MP_
n00b
Joined: 10 Nov 2003
Posts: 57
Location: Budapest, Hungary
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| Posted: Wed Jun 23, 2004 6:06 am Post subject: |
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That's _exactly_ what I wanted.  Thanks.
BTW if you use references, you need to use the previous one, which is also much easier to read.
Uh, one more thing:
Does the following also work?
| Code: |
$type = 'Example';
$example_object = new $type($arg1, $arg2 ...);
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Teetante
Guru
Joined: 02 Mar 2004
Posts: 515
Location: Oldenburg/Germany
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| Posted: Wed Jun 23, 2004 7:17 am Post subject: |
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I would be more than surprised if it didn't 
_________________
ICQ #81510866 - http://the-gay-bar.com - MSN tante@emptiness.de
Occam's Razor:
-"Entia non sunt multiplicanda praeter necessitatem."- |
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