how to split a file in not equally large parts?

[SarahS93]

szatox, thank you - it works!

if i have more than ten files, or generaly
how to create files they called part.01 part.02 part.03 .... part.10 part.11 ....
i will not have the files called part.1 part.2 part.3 .... part.10 part.11 ....
?

[Hu]

Your filename comes from the value of $counter, so if you want leading zeroes in the filename, include them in $counter. head seems to accept leading zeroes and ignore them.

[SarahS93]

.... head -c${i} > "part.0$counter" ....

created files like:
part.01
part.010
part.011
part.02
part.03
part.04
part.05
part.06
part.07
part.08
part.09

that is not what i want

[szatox]

There is some trick with printf, which allows you to specify output format for the parameters, including padding small integers with zeros to ensure constant length.
You can also check length of a string with ${#var}, and then prepend zeros as needed, like here
for i in {8..12}; do if [[ "${#i}" -lt 2 ]]; then echo "0${i}"; else echo "$i"; fi; done

Also, be careful with using 0-padded numbers, bash (and possibly other shells) can interpret them as base 8 integers, which means everything will work as expected in range of 00-07, and then crash when you reach 08 (which is a valid string, but not a valid integer).
Check this out for example:
for i in {05..10}; do echo $((i+1)); done

We don't usually think types when dealing with shell, but there are some cases where it matters.
_________________
Make Computing Fun Again

[Hu]