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Small alsasound init script "problem"
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obmun
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Joined: 17 Jan 2004
Posts: 66
Location: Europe (Spain)

PostPosted: Sun Feb 08, 2004 12:28 am    Post subject: Small alsasound init script "problem" Reply with quote

First I must say hello to everyone in the list, since it's the first time I'm posting. I've been working with Gentoo for aprox. 1 month now (with kernel 2.6.x) and alsa without problems. I was tired of having to unmute and setup again the mixer levels each time I restarted the computer and I added the alsasound script to boot level today. Obviously, it works :) but there was one small error I didn't like: alsasound was loading more than one time alsa modules with the consequent modprobe Fatal error message because some modules were loading as dependencies of other modules. Just after that I discovered that a few hours ago, the mantainers of alsa-utils had updated the script to avoid that errors.

Here's the important part: the modifications they introduced (obviously they check if the module is already loaded before modprobing it) doesn't work for me. The problem? If you see in this code:

Code:
[ -z `cut -d' ' -f1 /proc/modules | egrep "^${DRIVER}\$"` ]; then


they check if the next driver to be loded ($DRIVER variable) is loaded by listing modules. But (at least) in my gentoo the loaded module names have underscores (snd_ens1371) instead of the '-' of the module ko. The drivers to be loaded are obtained by doing a modprobe -c (that return the names with '-' from modules.conf). I thought using '-' in the module name was the usual. Am I wrong? Should I use the underscore in the modules.d files, or should be the alsasound script changed? Why do the names in the lsmod change to underscore?

Temporary, I have made the following change to my alsasound script:
Code:

         DRIVER="$(echo ${DRIVER} | sed 's/-/_/g')"
         if [ ! "${DRIVER}" = off ] &&
            [ -z `cut -d' ' -f1 /proc/modules | egrep "^${DRIVER}\$"` ]; then
, adding also the sed replace line in the sequencer loading part of alsasound script.

I almost don't do any coding in bash, so if it's a simpler way of doing that substitution please tell me.

Thank you in advance for your answers.
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infirit
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Joined: 11 Jan 2003
Posts: 778
Location: Hoofddorp / The Netherlands

PostPosted: Sun Feb 08, 2004 11:02 am    Post subject: Reply with quote

I'm no scripting genius but your problem/solutions sounds logical. Please can you report it in bugzilla BUG# 32045
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