Can Samba/Linux do this ?

[paulr]

Hi.

What I want to do is have a Linux Fileserver. You click on the share on Windows, it pops up a login box, and then Windows attaches the appropriate directory to a drive (say E, so I can set up multiple users on Windows (XP/9 without having the faff of umpteen Windows logins.

Basically pretty similar to how Linux itself works, where you log in as a user and this gives you a $HOME directory where people can store things.

I've been struggling with Samba (probably XP), but whilst I can log in happily with smbclient I can't get *!*!*"* XP to connect, even though the hardware is right.

Is there a way to get rid of the Windross so I can simply connect a directory (effectively) to Windows without going through the useless XP/98 "Networking".

[kezzla]

For WinXP:

[Pachacamac]

# Paramètre de connection utilisateur :
logon drive = P:
logon home = \\%L\%U\profile
logon path = \\%L\%U\profile

Each user will have a drive mounted during the boott called P:

[beowulf25]

Doesn't the [homes] share in smb.conf automatically do this? It's been a while since I used it, and things may have changed in the intervening year or two, but I seem to remember a users ~ showing up as a share on the samba box in Network Neighborhood. You can then map a drive to \\LinuxServer\username and set it to reconnect at login.

There is also a way to map the windows username to the linux account... if they are different - /etc/samba/smbusers.

Like I said, I don't worry about usernames on my home network, so I have all windows machines come in as (windows username) guest - which is mapped to (linux account) nobody - with permission to a public share for file sharing.

edit:

Also - doesn't WinXP try to encrypt the passwords automatically? You have to tell samba to use the encryption - may only apply to Domains though.

[Pachacamac]

With logon home and logon path (home / path are different if you use NT, 2000 or others) you don't need to use windows to map a drive.

It is two ways but they go in the same point.